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The PHP array_replace() function replaces the values of the first array with the values from following arrays.
- If a key from array1 exists in array2, values from array1 will be replaced by the values from array2; if the key only exists in array1, it will be left as it is
- If a key exist in array2 and not in array1, it will be created in array1
- If multiple arrays are used, values from later arrays will overwrite the previous ones
'Lamborghini', 'Car 2' => 'Ferrari');
$a2 = array('Car 2' => 'Maserati', 'Car 3' => 'Alfa Romeo');
print_r(array_replace($a1, $a2));
?>
Note
Arrays count starting from zero NOT one. So item 1 is position [0], item 2 is position [1], and item 3 is position [2] ... and so on.
Output
Array ( [Car 1] => Lamborghini [Car 2] => Maserati [Car 3] => Alfa Romeo )
Syntax
array_replace(array1, array2, array3, ...)
Parameters
Parameter | Description |
---|---|
array1 | Specifies an array (required) |
array2 | Specifies an array which will replace the values of array1 |
array3, ... | Specifies additional arrays to replace the values of array1 and array2, etc.; values from later arrays will overwrite the previous ones |
We’d like to acknowledge that we learned a great deal of our coding from W3Schools and TutorialsPoint, borrowing heavily from their teaching process and excellent code examples. We highly recommend both sites to deepen your experience, and further your coding journey. We’re just hitting the basics here at 1SMARTchicken.
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PHP NOTES:
- When using PHP, single or double quotation marks are acceptable and work identically to one another; choose whichever you prefer, and stay consistent
- Arrays count starting from zero NOT one; so item 1 is position [0], item 2 is position [1], and item 3 is position [2] … and so on
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